Today's puzzle

There are five different types of gems in a bag. There is one gem of the first type, two of the second type, three of the third type, 4 of the fourth type and five of the fifth type. From the information given below, can you tell how many there are of each kind?

• There are three more emeralds than aquamarines.
• There is an even number of opals and an odd number of peridots.
• There are fewer agates than aquamarines.

To participate in the contest, please do the following:

1. Upvote the post.

2. Send your answer to me either as a private message on Discord (@ksolymosi#5065) or in an e-mail message ([email protected]). If you use Discord, please make sure that your Discord name is the same as your Steemit name, otherwise, it will be difficult for me to find you...

3. Comment on the post containing the puzzle mentioning where I should look for your answer (for example „Answer sent via Discord").

Important

Don't post your solution under the post containing the puzzle because then you ruin the game of others!

The answer should contain the identification number of the puzzle, too (for example DBG 11).

Answers should arrive until I post the results of the actual game (usually between 12.00 am and 8.00 pm UTC+1, but exceptions might occur...). This leaves approximately a 12-24 hour time window to send me your answers. (Answers arriving later will not be considered.)

It is possible to correct your answer by sending another solution, but only the last message will be considered for the reward. (So if you send the good answer first and then send another message with a wrong one, then, unfortunately, the wrong one will „participate" in the game.)

Please do not ask clarifying questions. I do my best to phrase instructions as clearly as possible. So everyone should work from the amount of information given in the post.

Detailed rules and information on the scoring and rewards can be found here and here.

Source of images:
Cover
Author: Julia Freeman-Woolpert (a member of freeimages.com)
Banner
Author: Lisa Kong (a member of freeimages.com)

All other images and pictures are made by me.