Integrales con funciones exponenciales
Calcule la integral indefinida:
∫(e2x)/(ex + 3) dx
Usemos cambio de variable para resolver esta integral.
(1) Sea u= ex + 3
Obtengamos du
(2) du= ex dx
Despejemos ex de (1)
(3) ex= u - 3
Recordemos que:
(4) e2x= ex ex
Sustituyamos (4) en la integral
(5)∫(e2x)/(ex + 3) dx=∫(exex)/(ex + 3) dx= ∫(ex)/(ex + 3) (ex)dx
Sustituyendo (1), (2) y (3) en (5)
∫(ex)/(ex + 3) (ex)dx=∫(u - 3)/(u) du= ∫(u/u - 3/u) du= ∫(1 - 3/u) du= ∫du - 3∫(1/u)du= u - 3Ln|u| +C
Sustituyendo "u" por su valor de acuerdo a (1)
El resultado definitivo es:
∫(e2x)/(ex + 3) dx = ex + 3 - 3Ln|ex + 3| +C
Ejercicio # 25 de la Sección 8.4 de "El Cálculo" con geometría analítica. Louis Leithold. Segunda edición. Harla, S.A de C.V.
Released on: May 14th
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