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RE: SBD below 1$, dont use 50/50 payouts!

in #sbd5 years ago

I was called to perform a provably fair random drawing for @reversed-bidbot!

There are a 972 tickets participating in this round.
@inversionistam holds tickets number 0 - 7
@curatorbot holds tickets number 8 - 21
@abcor holds tickets number 22 - 25
@johnspalding holds tickets number 26 - 33
@freebornsociety holds tickets number 34 - 49
@johnvibes holds tickets number 50 - 51
@oups holds tickets number 52 - 97
@reversed-bidbot holds tickets number 98 - 105
@freebornangel holds tickets number 106 - 199
@fulcrumleader holds tickets number 200 - 204
@antisocialists holds tickets number 205 - 209
@dhimmel holds tickets number 210 - 937
@jasonliberty holds tickets number 938 - 947
@frdem3dot0 holds tickets number 948 - 971
The merkle root of the block in which this post will appear determines the winner.

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The block in which the above post is included has a merkle root of da1e2576fc15ef8345ccf8ed1a98ddf0c2d80453.
To find the winner we:

  1. Convert the merkle root into base 10:
    da1e2576fc15ef8345ccf8ed1a98ddf0c2d80453 = 1245232274038531057845150906205999365091361293395.
  2. Compute the residual after dividing by the number of tickets: 1245232274038531057845150906205999365091361293395 mod 972 = 831.
  3. This is the winning ticket, held by @dhimmel.

Congratulations!

Cool what do I win... or is this just a proof of concept? What determines who has tickets?

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